一、<b >一</b><b >.</b><b>选择题</b>
-
1.
设全集U=R,集合M={x||x﹣
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmfrac%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmfrac%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
|
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmo%3E%E2%89%A4%3C%2Fmo%3E%3Cmfrac%3E%3Cmn%3E5%3C%2Fmn%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmfrac%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
},P={x|﹣1≤x≤4},则(∁
UM)∩P等于( )
A . {x|﹣4≤x≤﹣2}
B . {x|﹣1≤x≤3}
C . {x|3<x≤4}
D . {x|3≤x≤4}
-
A . ﹣1+i
B . ﹣1﹣i
C . 1+i
D . 1﹣i
-
3.
若函数y=f(x)定义在[﹣1,2]上,且满足f(﹣
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmfrac%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmfrac%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
)<f(1),则f(x)在区间[﹣1,2]上是( )
A . 增函数
B . 减函数
C . 先减后增
D . 无法判断其单调性
-
4.
设命题甲:关于x的不等式x2+2ax+4≤0有解,命题乙:设函数f(x)=loga(x+a﹣2)在区间(1,+∞)上恒为正值,那么甲是乙的( )
A . 充分而不必要条件
B . 必要而不充分条件
C . 充要条件
D . 既不充分也不必要条件
-
5.
设a=log0.80.9,b=log1.10.9,c=1.10.9 , 则a,b,c的大小关系为( )
A . b<a<c
B . a<c<b
C . a<b<c
D . c<a<b
-
6.
已知函数y=f(x)在定义域[﹣2,4]上是单调减函数,且f(a+1)>f(2a),则a的取值范围是( )
A . 1<a≤2
B . ﹣1<a≤1
C . ﹣3<a≤3
D . a<﹣
-
7.
设函数f(x)=
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmrow%3E%3Cmo%3E%7B%3C%2Fmo%3E%3Cmrow%3E%3Cmtable%3E%3Cmtr%3E%3Cmtd%3E%3Cmrow%3E%3Cmsup%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmo%3E%2B%3C%2Fmo%3E%3Cmi%3Eb%3C%2Fmi%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmo%3E%2B%3C%2Fmo%3E%3Cmi%3Ec%3C%2Fmi%3E%3Cmi%3E++%EF%BC%8C+%3C%2Fmi%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmo%3E%E2%89%A4%3C%2Fmo%3E%3Cmn%3E0%3C%2Fmn%3E%3C%2Fmrow%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3Cmtr%3E%3Cmtd%3E%3Cmrow%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmi%3E++%EF%BC%8C+%3C%2Fmi%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmi%3E%26gt%3B%3C%2Fmi%3E%3Cmn%3E0%3C%2Fmn%3E%3C%2Fmrow%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3C%2Fmtable%3E%3C%2Fmrow%3E%3C%2Fmrow%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
,若f(﹣4)=2,f(﹣2)=﹣2,则关于x的方程f(x)=x的解的个数为( )
A . 1
B . 2
C . 3
D . 4
-
8.
已知函数f(x)是定义在R上的偶函数,且在区间[0,+∞]上单调递增,若实数a满足f(log
2a)+f(
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmi%3El%3C%2Fmi%3E%3Cmi%3Eo%3C%2Fmi%3E%3Cmsub%3E%3Cmi%3Eg%3C%2Fmi%3E%3Cmrow%3E%3Cmfrac%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmfrac%3E%3C%2Fmrow%3E%3C%2Fmsub%3E%3Cmi%3Ea%3C%2Fmi%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
)≤2f(1),则a的取值范围是( )
A . [1,2]
B . (0,
]
C . (0,2]
D . [
,2]
二、<b >二</b><b >.</b><b>填空题</b>
-
9.
已知i为虚数单位,若复数z=(m2+2m﹣3)+(m﹣1)i是纯虚数,则实数m=.
-
10.
设全集U={x∈Z|﹣2≤x≤4},A={﹣1,0,1,2,3},若B⊆∁UA,则集合B的个数是.
-
11.
设函数f(x)=
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmrow%3E%3Cmo%3E%7B%3C%2Fmo%3E%3Cmrow%3E%3Cmtable%3E%3Cmtr%3E%3Cmtd%3E%3Cmrow%3E%3Cmsup%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmo%3E%2B%3C%2Fmo%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmrow%3E%3Cmo%3E%28%3C%2Fmo%3E%3Cmrow%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmo%3E%E2%89%A4%3C%2Fmo%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmrow%3E%3Cmo%3E%29%3C%2Fmo%3E%3C%2Fmrow%3E%3C%2Fmrow%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3Cmtr%3E%3Cmtd%3E%3Cmrow%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmrow%3E%3Cmo%3E%28%3C%2Fmo%3E%3Cmrow%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmi%3E%26gt%3B%3C%2Fmi%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmrow%3E%3Cmo%3E%29%3C%2Fmo%3E%3C%2Fmrow%3E%3C%2Fmrow%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3C%2Fmtable%3E%3C%2Fmrow%3E%3C%2Fmrow%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
,若f(x
0)=8,则x
0=
.
-
-
13.
已知函数f(x)=ax2﹣2ax+2+b(a≠0)在[2,3]上有最大值5和最小值2,则a,b的值为.
-
14.
已知函数f(x)=
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmrow%3E%3Cmo%3E%7B%3C%2Fmo%3E%3Cmrow%3E%3Cmtable%3E%3Cmtr%3E%3Cmtd%3E%3Cmrow%3E%3Cmrow%3E%3Cmo%3E%7C%3C%2Fmo%3E%3Cmrow%3E%3Cmi%3El%3C%2Fmi%3E%3Cmi%3Eo%3C%2Fmi%3E%3Cmsub%3E%3Cmi%3Eg%3C%2Fmi%3E%3Cmn%3E3%3C%2Fmn%3E%3C%2Fmsub%3E%3Cmi%3Ex%3C%2Fmi%3E%3C%2Fmrow%3E%3Cmo%3E%7C%3C%2Fmo%3E%3C%2Fmrow%3E%3Cmi%3E++%EF%BC%8C+%3C%2Fmi%3E%3Cmn%3E0%3C%2Fmn%3E%3Cmi%3E%26lt%3B%3C%2Fmi%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmo%3E%E2%89%A4%3C%2Fmo%3E%3Cmn%3E3%3C%2Fmn%3E%3C%2Fmrow%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3Cmtr%3E%3Cmtd%3E%3Cmrow%3E%3Cmfrac%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E8%3C%2Fmn%3E%3C%2Fmfrac%3E%3Cmsup%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmo%3E%E2%88%92%3C%2Fmo%3E%3Cmfrac%3E%3Cmn%3E3%3C%2Fmn%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmfrac%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmo%3E%2B%3C%2Fmo%3E%3Cmfrac%3E%3Cmrow%3E%3Cmn%3E35%3C%2Fmn%3E%3C%2Fmrow%3E%3Cmn%3E8%3C%2Fmn%3E%3C%2Fmfrac%3E%3Cmi%3E++%EF%BC%8C+%3C%2Fmi%3E%3Cmi%3Ex%3C%2Fmi%3E%3Cmi%3E%26gt%3B%3C%2Fmi%3E%3Cmn%3E3%3C%2Fmn%3E%3C%2Fmrow%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3C%2Fmtable%3E%3C%2Fmrow%3E%3C%2Fmrow%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
,若函数g(x)=f(x)﹣m存在4个不同的零点x
1 , x
2 , x
3 , x
4 , 则实数m的取值范围是
,x
1•x
2•x
3•x
4的取值范围是
.
三、<b >三</b><b >.</b><b>解答题</b>
-
15.
已知集合A={x|x2﹣ax+a2﹣19=0},集合B={x|x2﹣5x+6=0},C={x|x2+2x﹣8=0}.
-
-
-
16.
已知关于x的函数y=(m+6)x2+2(m﹣1)x+m+1恒有零点.
-
-
(2)
若函数有两个不同零点,且其倒数之和为﹣4,求m的值.
-
17.
已知函数f(x)=﹣x3+3x2+9x+a(a为常数).
-
-
(2)
若f(x)在区间[﹣2,2]上的最大值是20,求f(x)在该区间上的最小值.
-
18.
已知函数f(x)=3x的定义域为R,满足f(a+2)=18,函数g(x)=λ•3ax﹣4x的定义域为[0,1].
-
-
(2)
若函数g(x)为定义域上单调减函数,求实数λ的取值范围;
-
(3)
λ为何值时,函数g(x)的最大值为
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmfrac%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmfrac%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
.
-
19.
已知函数f(x)=(a﹣
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmfrac%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmfrac%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
)x
2+lnx(a为实数).
-
(1)
当a=0时,求函数f(x)在区间[
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmfrac%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmi%3Ee%3C%2Fmi%3E%3C%2Fmfrac%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
,e]上的最大值和最小值;
-
(2)
若对任意的x∈(1,+∞),g(x)=f(x)﹣2ax<0恒成立,求实数a的取值范围.