①CH4(g)+O2(g)=CO(g)+H2(g)+H2O(g)△H=﹣321.5kJ/mol
②CH4(g)+H2O(g)=CO(g)+3H2(g)△H=+250.3kJ/mol
③CO(g)+2H2(g)=CH3OH(g)△H=﹣90.0kJ/mol
CH4(g)与O2(g)反应生成CH3OH(g)的热化学方程式为.
①A(g)+2B(g)⇌2C(g)+2D(l)△H1=﹣250.kJ•mol﹣1 K1=0.2
②E(s)+B(g)⇌C(g)△H2=﹣310kJ•mol﹣1K2=2
③F(g)+ B(g)⇌D(l)△H3=﹣200kJ•mol﹣1K3=0.8
T/min | n(X)/mol | n(Y)/mol | n(Z)/mol |
0 | 0.80 | 1.00 | 0 |
1 | 0.70 | 0.80 | |
5 | 0.70 | ||
9 | 0.40 | ||
10 | 0.40 | 0.80 |
①10min时改变的反应条件是
②t3时刻改变的反应条件是t5时刻改变的反应条件是,理由是.